Get the complete notes on an area related to circles for class 10 is provided here. The concepts related to circles such as area, circumference, segment, sector, angle and length of a circle, area for the sector of a circle are provided here. Also, the visualization of some plane and solid figures areas are discussed here.

Students can refer to the short notes and MCQ questions along with separate solution pdf of this chapter for quick revision from the links below:

Areas related to circles Short Notes

Areas related to circles MCQ Practice Questions

Areas related to circles MCQ Practice Solutions

Introduction

For More Information On Circles, Watch The Below Videos.

Area of a Circle

Area of a circle is $\pi r^2$, where $\pi =$$\mathrm{22/7\; o}r\approx 3.14$ (can be used interchangeably for problem-solving purposes)and r is the radius of the circle.
$\pi$ is the ratio of the circumference of a circle to its diameter.

For More Information On Area Of Circle, Watch The Below Video.

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Circumference of a Circle

The perimeter of a circle is the distance covered by going around its boundary once. The perimeter of a circle has a special name: Circumference, which is π times the diameter which is given by the formula $2\pi r$

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Segment of a Circle

A circular segment is a region of a circle that is “cut off” from the rest of the circle by a secant or a chord.

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Sector of a Circle

A circle sector/ sector of a circle is defined as the region of a circle enclosed by an arc and two radii. The smaller area is called the minor sector and the larger area is called the major sector.

For More Information On Parts Of A Circle, Watch The Below Video.

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Angle of a Sector

The angle of a sector is the angle that is enclosed between the two radii of the sector.

Length of an arc of a sector

The length of the arc of a sector can be found by using the expression for the circumference of a circle and the angle of the sector, using the following formula:

$L=\; ($θ/360°)$\times 2\pi r$

Where $\theta$ is the angle of sector and $r$ is the radius of the circle.

Area of a Sector of a Circle

Area of a sector is given by

$($θ/360°)$\times \pi r^2$

where $\angle \theta$ is the angle of this sector(minor sector in the following case) and r is its radius

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Area of a Triangle

The Area of a triangle is,
$Area=(1/2)\times base\times height$
If the triangle is an equilateral then
$Are\mathrm{a=(\surd }$$3/4)\times a^2$  where “$\mathrm{a”}$ is the side length of the triangle.

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Area of a Segment of a Circle

Area of segment APB (highlighted in yellow)
= (Area of sector OAPB) – (Area of triangle AOB)

$=[(\varnothing /360°)\times \pi r2$] – [(1/2)$\times AB\times OM]$

[To find the area of triangle AOB, use trigonometric ratios to find OM (height) and AB (base)]

Also, the Area of segment APB can be calculated directly if the angle of the sector is known using the following formula.

 $=[(\theta /360°)\times \pi r2]\; –\; [r2\times sin \theta /2 \times \; cos\theta /2]$

Where $\theta$ is the angle of the sector and $r$ is the radius of the circle
All these formulas are tabulated as given below for quick revision.

Parameters of Circles	Formulas
Area of the sector of angle θ	(θ/360°) × πr2
Length of an arc of a sector of angle θ	(θ/360°) × 2πr
Area of major sector	πr2 – (θ/360°) × πr2
Area of a segment of a circle	Area of the corresponding sector – Area of the corresponding triangle
Area of the major segment	πr2 – Area of segment (minor segment)

Visualizations

Areas of different plane figures

–    Area of a square (side l) $=l^2$
–    Area of a rectangle $=l\times b,$ where $l$ and $b$ are the length and breadth of the rectangle
–    Area of a parallelogram $=b\times h,$ where “$\mathrm{b”}$ is the base and “$\mathrm{h”}$ is the perpendicular height.

Area of a trapezium $=[$$(a+b)\times \mathrm{h]/2},$

where

$a$ & $b$ are the length of the parallel sides

h is the trapezium height

Area of a rhombus $=$$pq/2,$ where $p$ & $q$ are the diagonals.

For More Information On Visualizing Areas of different plane figures, Watch The Below Video.

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Areas of Combination of Plane figures

For example: Find the area of the shaded part in the following figure: Given the ABCD is a square of side 28 cm and has four equal circles enclosed within.

Looking at the figure we can visualize that the required shaded area = $A\left(squareABCD\right)-4\times A\left(Circle\right)$.

Also, the diameter of each circle is 14 cm.
$=\left(l^2\right)-4\times \left(\pi r^2\right)$
$=\left({28}^2\right)-[4\times (\pi \times 49\left)\right]$
$=784-[\mathrm{4\times 22/7}\times 49]$
$=784-616$
$=168c{m}^2$