Slope Intercept Form
In geometry, the equation of a line can be written in different forms and each of these representations is useful in different ways. The equation of a straight line is written in either of the following methods:

 Point slope form
 Two point form
 Slope intercept form
 Intercept form
In this article, you will learn about one of the most common forms of the equation of lines called slopeintercept form along with derivation, graph and examples.
Learn what is the intercept of a line here.
Let’s have a look at the slopeintercept form definition.
What is the Slope Intercept Form of a Line?
The graph of the linear equation y = mx + c is a line with m as slope, m and c as the yintercept. This form of the linear equation is called the slopeintercept form, and the values of m and c are real numbers.
The slope, m, represents the steepness of a line. The slope of the line is also termed as gradient, sometimes. The yintercept, b, of a line, represents the ycoordinate of the point where the graph of the line intersects the yaxis.
Slope Intercept Form Equation
In this section, you will learn the derivation of the equation of a line in the slopeintercept form.
Consider a line L with slope m cuts the yaxis at a distance of c units from the origin.
Here, the distance c is called the yintercept of the given line L.
So, the coordinate of a point where the line L meets the yaxis will be (0, c).
That means, line L passes through a fixed point (0, c) with slope m.
We know that, the equation of a line in point slope form, where (x_{1}, y_{1}) is the point and slope m is:
(y – y_{1}) = m(x – x_{1})
Here, (x_{1}, y_{1}) = (0, c)
Substituting these values, we get;
y – c = m(x – 0)
y – c = mx
y = mx + c
Therefore, the point (x, y) on the line with slope m and yintercept c lies on the line if and only if y = mx + c
Note: The value of c can be positive or negative based on the intercept is made on the positive or negative side of the yaxis, respectively.
Slope Intercept Form Formula
As derived above, the equation of the line in slopeintercept form is given by:
y = mx + c
Here,
(x, y) = Every point on the line
m = Slope of the line
c = yintercept of the line
Usually, x and y have to be kept as the variables while using the above formula.
Slope Intercept Form x Intercept
We can write the formula for the slopeintercept form of the equation of line L whose slope is m and xintercept d as:
y = m(x – d)
Here,
m = Slope of the line
d = xintercept of the line
Sometimes, the slope of a line may be expressed in terms of tangent angle such as:
m = tan θ
Also, try: Slope Intercept Form Calculator
Derivation of SlopeIntercept Form from Standard Form Equation
We can derive the slopeintercept form of the line equation from the equation of a straight line in the standard form as given below:
As we know, the standard form of the equation of a straight line is:
Ax + By + C = 0
Rearranging the terms as:
By = Ax – C
⇒y = (A/B)x + (C/B)
This is of the form y = mx + c
Here, (A/B) represents the slope of the line and (C/B) is the yintercept.
Slope Intercept Form Graph
When we plot the graph for slopeintercept form equation we get a straight line. Slopeintercept is the best form. Since it is in the form “y=”, hence it is easy to graph it or solve word problems based on it. We just have to put the xvalues and the equation is solved for y.
The best part of the slopeintercept form is that we can get the value of slope and the intercept directly from the equation.
Solved Examples
Example 1:
Find the equation of the straight line that has slope m = 3 and passes through the point (–2, –5).
Solution:
By the slopeintercept form we know;
y = mx+c
Given,
m = 3
As per the given point, we have;
y = 5 and x = 2
Hence, putting the values in the above equation, we get;
5 = 3(2) + c
5 = 6+c
c = 5 + 6 = 1
Hence, the required equation will be;
y = 3x+1
Example 2:
Find the equation of the straight line that has slope m = 1 and passes through the point (2, 3).
Solution:
By the slopeintercept form we know;
y = mx+c
Given,
m = 1
As per the given point, we have;
y = 3 and x = 2
Hence, putting the values in the above equation, we get;
3 = 1(2) + c
3 = 2 + c
c = 3+2 = 1
Hence, the required equation will be;
y = x1
Example 3:
Find the equation of the lines for which tan θ = 1/2, where θ is the inclination of the line such that:
(i) yintercept is 5
(ii) xintercept is 7/3
Solution:
Given, tan θ = 1/2
So, slope = m = tan θ = 1/2
(i) yintercept = c = 5
Equation of the line using slope intercept form is:
y = mx + c
y = (1/2)x + (5)
Or
2y = x – 10
x – 2y – 10 = 0
(ii) xintercept = d = 7/3
Equation of slope intercept form with xintercept is:
y = m(x – d)
y = (1/2)[x – (7/3)]
Or
2y = (3x – 7)/3
6y = 3x – 7
3x – 6y – 7 = 0
Practice Problems
 Find the slope of the line y = 5x + 2.
 Find the slope of the line which crosses the line at point (2,6) and have an intercept of 3.
 What is the equation of the line whose angle of inclination is 45 degrees and xintercept is ⅗?
 Write the equation of the line passing through the point (0, 0) with slope 4.