Table of 28
In this, we will read and memorize the table of 28. You can also download the 28 times table image from here for further reference. Multiplication tables help us to solve the mathematical problems easily and quickly. Let’s look at the table here.
Table of 28 Charts (28 Times Table)
Tables from 1 to 20 are important to study the further numbers tables.
| 28 | X | 1 | = | 28 |
| 28 | X | 2 | = | 56 |
| 28 | X | 3 | = | 84 |
| 28 | X | 4 | = | 112 |
| 28 | X | 5 | = | 140 |
| 28 | X | 6 | = | 168 |
| 28 | X | 7 | = | 196 |
| 28 | X | 8 | = | 224 |
| 28 | X | 9 | = | 252 |
| 28 | X | 10 | = | 280 |
| 28 | X | 11 | = | 308 |
| 28 | X | 12 | = | 336 |
| 28 | X | 13 | = | 364 |
| 28 | X | 14 | = | 392 |
| 28 | X | 15 | = | 420 |
| 28 | X | 16 | = | 448 |
| 28 | X | 17 | = | 476 |
| 28 | X | 18 | = | 504 |
| 28 | X | 19 | = | 532 |
| 28 | X | 20 | = | 560 |
28 Times Table
Repeatedly adding by 28’s gives the table of 28.
(i) When 2 packs each having 28 pastel colours.
By repeated addition we can show 28 + 28 = 56
Then, twenty-eight times 2 is
2 × 28 = 56
Therefore, there are 56 pastel colours.
(ii) When 3 bunches of 28 bananas each.
By repeated addition we can show 28 + 28 + 28 =84 Then, twenty-eight times 3 is
3 × 28 = 84
Therefore, there are 84bananas.
(iii) When 4 bunches of 28 bananas each.
By repeated addition we can show 28 + 28 + 28 +28 = 112
Then, twenty-eight times 4 is
4 × 28 = 112
Therefore, there are 112 bananas.
(iv) When 5 bunches of 28 bananas each.
By repeated addition we can show 28 + 28 + 28 + 28 +28 = 140
Then, twenty-eight times 5 is
5 × 28 = 140
Therefore, there are 140 bananas.
(v) When 6 bunches of 28 bananas each.
By repeated addition we can show 28 + 28 + 28 + 28 + 28 + 28 = 168
Then, twenty-eight times 6 is
6 × 28 = 168
Therefore, there are 168 bananas.
(vi)When 7 bunches of 28 bananas each.
By repeated addition we can show 28 + 28 + 28 + 28 + 28 + 28 +28 = 196
Then, twenty-eight times 7 is
7 × 28 = 196
Therefore, there are 196 bananas.
(vii) When 8 bunches of 28 bananas each.
By repeated addition we can show 28 + 28 + 28 + 28 + 28 + 28 + 28 + 28 = 224
Then, twenty-eight times 8 is
8 × 28 = 224
Therefore, there are 224 bananas.
(viii) When 9 bunches of 28 bananas each.
By repeated addition we can show 28 + 28 + 28 + 28 + 28 + 28 + 28 + 28 +28 = 252
Then, twenty-eight times 9 is
9 × 28 = 252
Therefore, there are 252 bananas.
(ix) When 10 bunches of 28 bananas each.
By repeated addition we can show 28 + 28 + 28 + 28 + 28 + 28 + 28 + 28 +28 +28 = 280
Then, twenty-eight times 10 is
10 × 28 = 280
Therefore, there are 280 bananas.
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