Trigonometric Ratios of Complementary Angles
In Mathematics, the complementary angles are the set of two angles such that their sum is equal to 90°. For example, 30° and 60° are complementary to each other as their sum is equal to 90°. In this article, let us discuss in detail about the complementary angles and the trigonometric ratios of complementary angles with examples in a detailed way.
Complementary Angles Definition
The two angles, say ∠X and ∠Y are complementary if,
∠X + ∠Y = 90°
In such a condition ∠X is known as the complement of ∠Y and vice-versa.
In a right angle triangle, as the measure of the right angle is fixed, the remaining two angles always form the complementary as the sum of angles in a triangle is equal to 180°.
Finding Trigonometric Ratios of Complementary Angles
Assume a triangle ∆ABC, which is right-angled at B.
∠A and ∠C form a complementary pair.
⇒ ∠A + ∠C = 90°
The relationship between the acute angle and the lengths of sides of a right-angle triangle is expressed by trigonometric ratios. For the given right angle triangle, the trigonometric ratios of ∠A is given as follows:
sin A = BC/AC
cos A = AB/AC
tan A =BC/AB
csc A = 1/sin A = AC/BC
sec A =1/cos A = AC/AB
cot A = 1/tan A = AB/BC
The trigonometric ratio of the complement of ∠A. It means that the ∠C can be given as 90° – ∠A
As ∠C = 90°- A (A is used for convenience instead of ∠A ), and the side opposite to 90° – A is AB and the side adjacent to the angle 90°- A is BC as shown in the figure given above.
sin (90°- A) = AB/AC
cos (90°- A) = BC/AC
tan (90°- A) = AB/BC
csc (90°- A) =1/sin (90°- A) = AC/AB
sec (90°- A) = 1/cos (90°- A) = AC/BC
cot (90°- A) = 1/tan (90°- A) = BC/AB
Comparing the above set of ratios with the ratios mentioned earlier, it can be seen that;
sin (90°- A) = cos A ; cos (90°- A) = sin A
tan (90°- A) = cot A; cot (90°- A) = tan A
sec (90°- A) = csc A; csc (90°- A) = sec A
These relations are valid for all the values of A that lies between 0° and 90°.
- Sin of an angle = Cos of its complementary angle
- Cos of an angle = Sin of its complementary angle
- Tan of an angle = Cot of its complementary angle
Trigonometric Ratios of Complementary Angles Examples
To have a better insight on trigonometric ratios of complementary angles consider the following example.
If A, B and C are the interior angles of a right-angle triangle, right-angled at B then find the value of A, given that tan 2A = cot(A – 30°) and 2A is an acute angle.
Using the trigonometric ratio of complementary angles,
cot (90°- A) = tan A
From this ratio, we can write the above expression as:
⇒ tan 2A = cot (90°- 2A) ….(1)
Given expression is tan 2A = cot (A – 30°) …(2)
Now, equate the equation (1) and (2), we get
cot (90°- 2A) = cot (A – 30°)
⇒ 90°- 2A = A – 30°
⇒3A = 90° + 30°
⇒3A = 120°
⇒A = 120°/ 3
⇒ A = 40°
Thus, the measure of the acute angle A can be easily calculated by making use of trigonometry ratio of complementary angles.
Trigonometric Ratios of Compound Angles
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