Uniform Distribution
What is Uniform Distribution
A continuous probability distribution is a Uniform distribution and is related to the events which are equally likely to occur. It is defined by two parameters, x and y, where x = minimum value and y = maximum value. It is generally denoted by u(x, y).
OR
If the probability density function or probability distribution of a uniform distribution with a continuous random variable X is f(b)=1/y-x, then It is denoted by U(x,y), where x and y are constants such that x<a<y. It is written as
X \(\sim\) U(a,b)
(Note: Check whether the data is inclusive or exclusive before working out problems with uniform distribution.)
Uniform Distribution Examples
Example: The data in the table below are 55 times a baby yawns, in seconds, of a 9-week-old baby girl.
10.4 | 19.6 | 18.8 | 13.9 | 17.8 | 16.8 | 21.6 | 17.9 | 12.5 | 11.1 | 4.9 |
12.8 | 14.0 | 22.8 | 20.8 | 15.9 | 16.3 | 13.4 | 17.1 | 14.5 | 19.0 | 22.8 |
1.3 | 0.7 | 8.9 | 11.9 | 10.9 | 7.3 | 5.9 | 3.7 | 17.9 | 19.2 | 9.8 |
5.8 | 6.9 | 2.6 | 5.8 | 21.7 | 11.8 | 3.4 | 2.1 | 4.5 | 6.3 | 10.7 |
8.9 | 9.7 | 9.1 | 7.7 | 10.1 | 3.5 | 6.9 | 7.8 | 11.6 | 13.8 | 18.6 |
- The sample mean = 11.49
- The sample standard deviation = 6.23.
As assumed, the yawn times, in secs, it follows a uniform distribution between 0 and 23 seconds(Inclusive).
So, it is equally likely that any yawning time is from 0 to 23.
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- Histograph Type: Empirical Distribution (It matches with theoretical uniform distribution).
If the length is A, in seconds, of a 9-month-old baby’s yawn.
- The uniform distribution notation for the same is A \(\sim\) U(x,y) where x = the lowest value of a and y = the highest value of b.
- f(a) = 1/(y-x), f(a) = the probability density function. For x \(\leq\)a\(\leq\)y.
In this example:
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- X \(\sim\) U(0,23)
f(a) = 1/(23-0) for 0 \(\leq\)X\(\leq\)23.
Theoretical Mean Formula
\(\mu\) = (x+y)/2 |
Standard Deviation Formula
\(\sigma\) = \(\sqrt{\frac{(y-x)^{2}}{12}}\) |
In this example,
The theoretical mean = \(\mu\) = (x+y)/2
\(\mu\) = (0+23)/2 = 11.50Standard deviation = \(\sqrt{ \frac{(y-x)^{2}}{12}}\)
Standard deviation = \(\sqrt{ \frac{(23-0)^{2}}{12}}\) =6.64 seconds.
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Learn more on Distribution | |
Normal Distribution Formula | Binomial Distribution Formula |