# Equation Of A Plane: 3 Non-Collinear Points

## Trigonometry # Equation Of A Plane: 3 Non-Collinear Points

The physical quantities which have magnitude, as well as directly attached to them, are known as vectors. Position vectors simply denote the position or location of a point in the three dimensional Cartesian systems with respect to a reference origin. In the upcoming discussion, we shall study about vectors and the Cartesian equation of a plane in three dimensions.

In the previous section we have already discussed that to a given vector there lie infinite planes which are perpendicular to it. But for a particular point there exist one and only one unique plane which is perpendicular to it passing through the given point. The vector equation of a plane in this case is given as

$$(\vec{r} – \vec{a}) . \vec{N} = 0$$

Here,  $$\vec{r}$$  and  $$\vec{a}$$ represent the position vectors.

The Cartesian equation of such a plane is represented by:

$$A(x-{x}_{1}) + B (y- {y}_{1}) + C (z -{z}_{1}) = 0$$

Here, A, B, and C are the direction ratios.

Let us now discuss the equation of a plane passing through three points which are non-collinear.

## Equation of a Plane Passing through Three Non Collinear Points

Let us consider three non collinear points P, Q, R lying on a plane such that their position vectors are given by $$\vec{a}$$ , $$\vec{b}$$   and $$\vec{c}$$  as shown in the figure given below. The vectors  $$\vec{PQ}$$ and  $$\vec{PR}$$ lie in the same plane. The vector lying perpendicular to plane containing the points P, Q and R is given by   $$\vec{PQ}$$ × $$\vec{PR}$$ . If  is the position vector of any point A lying in the plane containing P, Q, R then using the vector equation of a plane as mentioned above, the equation of the plane passing through P and perpendicular to the vector $$\vec{PQ}$$ × $$\vec{PR}$$  is given by

($$\vec{r}$$$$\vec{a}$$). ($$\vec{PQ}$$ × $$\vec{PR}) = 0$$

Also, from the above figure,  and . Substituting these values in the above equation, we have

$$(\vec{r} – \vec{a}).[(\vec{b}- \vec{a}) × (\vec{c}- \vec{a})] = 0$$

This represents the equation of a plane in vector form passing through three points which are non- collinear.

To convert this equation in Cartesian system, let us assume that the coordinates of the point P, Q and R are given as (x1, y1, z1), (x2, y2, z2) and (x3, y3, z3) respectively. Also let the coordinates of point A be  x, y and z. Substituting these values in the equation of a plane in Cartesian form passing through three non-collinear points, we have This is the equation of a plane in Cartesian form passing through three points which are non- collinear.

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## Frequently Asked Questions on Equation of a Plane Passing Through 3 Non-collinear Points

### What is meant by the equation of a plane?

The equation of a plane defines the plane surface in the three-dimensional space.

### Mention two different forms of the equation of a plane?

The equation of a plane can be expressed in two different forms such as vector form and cartesian form.

### What are the different methods to derive the equation of a plane?

The equation of a plane can be derived using different methods, such as
Equation of a plane in normal form
Equation of a plane perpendicular to a given vector and through a point
Equation of a plane passing through three non-collinear points
Equation of a plane passing through the intersection of two given planes.

### Is one normal and one point sufficient to form the equation of a plane?

Yes, one normal and one point is sufficient to form the equation of a plane.

### What is the intercept form of the equation of a plane?

The intercept form of the equation of a plane is (x/a) +(y/b) +(z/c) =1. Here, a, b and c are the x-intercept, y-intercept and z-intercept respectively.